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3 years ago

Select which equations are POLYNOMIALS and which are NOT POLYNOMIALS.

1 answer:

6 0

In Polynomials all the exponents of x-variable must be positive integers, then polynomials are:
a) -x^5+7x-1/2x^2+9, the exponents of x's are: 5, 1, and 2
b) x^3-4x-3, the exponents of x's are: 3, and 1
f) x^4+x^3√7+2x^2-√3/2x+π, the exponents of x's are: 4, 3, 2, and 1

Not polynomials are:
c) 4 / x^2-4x+3 = 4x^(-2)-4x+3, the exponents of x's are -2, and 1
d) x^4+5/x^3-√x+8=x^4+5x^(-3)-x^(1/2)+8, the exponents of x's are 4, -3, and 1/2
e) |x|^2+4√x-2=|x|^2+4x^(1/2)-2, the exponents of x's are 2 and 1/2

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#29 is the only one I need

const2013 [10]

So the neat number is all the numbers added together I'm pretty sure or it's either all the numbers added together times the amount of numbers
There are

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%285x%20-%202%29%20%5Ctimes%20%28x%20%20%2B%202%29" id="TexFormula1" title="(5x - 2) \times (x

Mars2501 [29]

Answer:

5x^2 +8x-4

Step-by-step explanation:

(5x - 2) * (x + 2)

We can FOIL

first: 5x*x = 5x^2

outer : 2*5x = 10x

inner: -2x

last : -2*2 = -4

Add these together

5x^2 +10x-2x-4

5x^2 +8x-4

4 0

3 years ago

Find the set the solves <img src="https://tex.z-dn.net/?f=x%20%2B%20%20%20%5Cfrac%7B2%7D%7Bx%7D%20%20%20%5Cgeq%203" id="Tex

Nady [450]

Hello,
To exist x≠0

if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if

4 0

3 years ago

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!

lapo4ka [179]

Answer:

11,60,62

Hope this helps

4 0

2 years ago

Read 2 more answers

Branilest and 30 point please answer

Lynna [10]

Answer:

Addition Property of Equality

Step-by-step explanation:

System of Equations

When two equations are given and two variables are unknown in both equations, then we can solve the system in several ways.

One method consists in adding both equations term by term and eliminate one of the variables. That property is called the addition of equalities. Let's consider the equations given in the problem:

$5x+4y=-2\\2x-4y=6$

If we add both equations, we have

$5x+4y+2x-4y=-2+6$

Simplifying

$7x=4$

By adding both equations we managed to eliminate the variable y and could easily find the value of x

$x=4/7$

Answer: Addition Property of Equality

7 0

3 years ago