A family of bears is going to a movie. The following data points represent the ticket and candy price (in dollars) for each bear
1 answer:
<h2>Answer:</h2>
The interquartile range (IQR) of the data set is:
3.5
<h2>Step-by-step explanation:</h2>The data points are given as follows:
0, 1 1/2, 2 1/2, 3, 4, 4, 4, 7, 7 1/2
i.e. 0 , 1.5 , 2.5 , 3 , 4 , 4 , 4 , 7 , 7.5
There are a total of 9 data points and we know that the median of the data is the central tendency of the data and it always exist in the middle of the data.
Here we have 9 data points.
and hence the median exist at the the 5th place.
Hence, Median of data of Middle quartile i.e. = 4
- Also, the lower set of data is:
0 , 1.5 , 2.5 , 3
and the first quartile or the lower quartile i.e. is the median of the lower set of data.
i.e.
- The upper set of data is:
4 , 4 , 7 , 7.5
and the third quartile or the upper quartile i.e. is the median of the upper set of data.
i.e.
Hence, the interquartile range (IQR) of the data set is given by:
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The function increases in the interval (-∞, -3) and the function also increases in the interval (-1,∞) .
The given function is of the form
f(x) = x³ + 6x² + 8x
Now we take the first differentiation of the function
f'(x) = 2x² + 12x + 8
f'(x) = 2 (x² + 6x + 9) -10
f'(x) = 2(x+3)² - 10
Therefore at x = -3 , f'(x) = -10.
Hence the function is increasing in the interval of (-∞, -3)
Again f'(x) = 2x² + 12x + 8 , so after first differentiation we get :
That the function is also increasing in the interval (-1,∞)
Now for the interval (-4,-2), we can say that the graph of the function is positive as the y value increases and then decreases but all y values are positive as illustrated in the graph.
In the interval (0,∞) the function is strictly increasing and has positive values only.
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