Answer:
2. There is also an irrelevant joke that 1 plus 1 equals window.
Step-by-step explanation:
Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
Answer:
- The set
with x ≤ 0 and y ≤ 0 is not a vector space. - The 10th axiom
does not hold
Step-by-step explanation:
Let u, v and w be vectors in the vector space V, and let c and d be scalars. A set S is defined as a vector space if it satisfies the following conditions:
- 1.

- 2. v + w = w + v
- 3. (u + v) + w = u + (v + w)
- 4. v + 0 = v = 0 + v
- 5. v + (−v) = 0
- 6. 1v = v
- 8. c(v + w) = cv + cw
- 9. (c + d)v = cv + dv
- 10.

Given the set of all vectors x, y in
with x ≤ 0 and y ≤ 0
If the scalar c is such that
.
Therefore, the 10th axiom is not satisfied and thus the set
with x ≤ 0 and y ≤ 0 is not a vector space.