Answer:
Step-by-step explanation:
These are logically difficult, so it makes sense to me you're asking about this.
so A = 1/2 (big arc - small arc)
and 360 = big arc + small arc
then
360 - small arc = big arc
so rewrite the top equation
A = 1/2(360-small arc -small arc)
63 = 1/2( 360 - 2 small arc)
2* 63 = 360 - 2 small arc
126 = 360 - 2 small arc
2 small arc = 360-126
2small arc = 234
small arc = 234/2
small arc = 117
x = 117°
Answer:
A
Step-by-step explanation:
L*W
Answer:
24 possible outcomes
Step-by-step explanation:
Combination has to do with selection. For example, if r object is selected from a pool of n objects, the number if possible ways can be expressed according to the combination formula:
nCr = n!/(n-r)!r!
Applying this in question, if each student receives one of 4 calculator models and one of 3 types of ruler, the number of ways this can be done is:
4C1 × 3C1
4C1 = 4!/(4-1)!1! {If a student gets one calculator)
4C1 = 4×3×2/3×2
4C1 = 4ways
3C1 = 3!/(3-2)!1! {If a student gets a ruler}
3C1 = 3×2/1
3C1 = 6ways
Total number of possible outcomes if a student gets one ruler and one calculator will be 4×6 = 24ways
Answer:

Step-by-step explanation:
-p(d+z)=-2z+59
-pd-pz=-2z+59
lets bring all z integers on one side
-2z+pz = -pd-59
z(-2+p)=-pd-59
z = (pd-59) / (-2+p)