Question

1.solve for p

Answer 1

1. Answer;

p =-3/2p

Solution;

To solve for P  in the equation;

= 3(p + q ) = p

We open the brackets;

= 3p + 3q = p

Then, we combine the like terms together, we get;

   3p - p = -3q

Therefore; 2p = -3q

  hence;  p = -3/2q. 

2. Answers;

b = 19/2

Solution;

To solve for b when the value of a = 3

4a = 2b - 7

we substitute 3 with a in the equation

( 4 × 3 ) = 2b -7

12 = 2b -7

Then, make b the subject

19 = 2b

b = 19/2

3. Answer;

r =d/t

Solution;

To solve for r 

d= rt.

In order to get r, we divide both sides by t

d/t = rt/t

r =  d/t

4. Answer;

Width = 30 units

Solution;

The width of a rectangle with a given perimeter of 90 and length is 15.

The perimeter of a rectangle is given by;

Perimeter= 2(Length + Width)

Thus; Perimeter = 90 , length=15

90 = 2 (W + 15)

Dividing both sides by 2,

45 = w + 15

Subtracting from both sides;

W = 45 -15

W = 30

Therefore, the width of the rectangle is 30 units

Answer 2

1.
To solve for P = p3(p + q ) = p
We combine the P's together p - p3 - p = q
The p = 3/2q. 
The correct answer is D.
2.
To solve for b when the value of a = 3
4a = 2b - 7
we put 3 where there is a
( 4 × 3 ) = 2b -7
12 = 2b -7
19 = 2b
b = 19/2
The correct answer is C.

3. To solve for r 
d= rt.
In order to get r, we divide both sides by t
d/t = rt/t
r =  d/t
The correct answer is C.

4. The width of a rectangle with a given perimeter of 90 and length is 15.
The perimeter is the whole rectangle.
We are given length is 15.
To find width which is one side it should be,
90/15 = 30

Width is 30.
The correct answer is D.