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Arte-miy333 [17]
4 years ago
10

write the condition to be satisfied by q so that a rational number p/q has a terminating decimal expansion​

Mathematics
1 answer:
hjlf4 years ago
6 0
For a rational number to have a terminating decimal expansion
q should be in the form 5^m and 2^n or both. If q is not in the form of either then it is a non terminating recurring decimal expansion
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PLEASE PLEASE PLEASE HELP PLEASE!!!
ycow [4]

The answer to the question provided is 10.

Step-by-step explanation:

☆Cross multiply.

\frac{2x + 5}{20}  =  \frac{x + 5}{12}  \\  \\ 20(x + 5) = 12(2x + 5) \\  \:  \:  \: \:  \:  \:  \:  \:  \:  \:   20x + 100 = 24x + 60 \\   \frac{ - 24x  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  - 24x}{ - 4x + 100 = 60}  \\  \frac{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 100 =  - 100}{ \frac{ - 4x}{ - 4} =  \frac{ - 40}{ - 4}  }  \\ x = 10

♡Happy to help anytimes!♤

3 0
3 years ago
Explain how you can prove the difference of two cubes identity. a^3 – b^3 = (a – b)(a^2 + ab + b^2)
iris [78.8K]
Hello, It is very simples.

Look it :

Let a^3 - b^3 = ?

Add on both th side -3a^2b + 3ab^2

a^3 -3a^2b + 3ab^2 -b^3 = ?

-3a^2b+3ab^2

The firs equation is = (a - b)^3

Then,

(a - b)^3 = ? + 3a^2b - 3ab^2

Passing -3a^2b + 3ab^2 to the left side:
But changing the sinal

? = (a - b)^3 + 3a^2b - 3ab^2

? = (a - b)^3 + 3ab ( a - b)

Putting (a - b) as commun factor

? = (a - b).[ 3ab + (a - b)^2 ]

As (a - b)^2 = a^2 - 2ab + b^2

Then,

? = (a - b).[ 3ab + a^2 -2ab +b^2]

? = (a - b).( a^2 + ab + b^2)

I hope helps!

5 0
3 years ago
Read 2 more answers
Pls help I don't wanna get a bad grade
krok68 [10]

Answer:

i think 62.5% I believe sorry if I'm wrong

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Luis and his family flew 51487 miles last summer while on vacation rounded to the nearest thousand how many miles did they fly
ludmilkaskok [199]
In the given mathematical value of 51, 487 to round off this number to the nearest thousand, we can elaborate the number values using the expanded form to clearly see the order position: <span><span>1. </span><span> 50, 000 = ten thousands</span></span> <span><span>2. </span><span> 1, 000 = thousands</span></span> <span><span>3. </span><span> 400 = hundreds</span></span> <span><span>4. </span><span> 80 = tens</span></span> <span><span>5. </span><span> 7 = ones</span></span> Now we can observe the numerical value of 51, 487 than 1, 000 is the number in which belongs to the thousands’ position hence since the nearest number is 400 the value will be 51, 000.  



8 0
3 years ago
6th grade math help me plzzz
viva [34]

Answer:

The answer is A, B, and D

Step-by-step explanation:

This is really easy, all you have to do is to choose the answers that are less than 1.

Why? because anything less than 1 multiplied by a number gives you a smaller number.

Since C and E are bigger than 1 then they will give you a bigger number than 2/3.

But A, B, and D are less than 1.

So, the answer is A, B, and D

6 0
3 years ago
Read 2 more answers
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