1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ExtremeBDS [4]
2 years ago
13

SBC is an isosceles triangle with main vertex S.

Mathematics
1 answer:
stira [4]2 years ago
4 0

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

You might be interested in
Determine whether the graph represents a function . If it does represent a function , give its domain and range.
laiz [17]

Answer:

A function is a relationship that maps elements from a set (the domain) into elements from another set (the range)

Such that each element in the domain can be mapped into only one element from the range.

Let's see graphs 18, 20,24 and 30.

Remember that the axis that represents the domain is the horizontal one (usually represented with x), and the vertical axis represents the range (usually represented with y)

18) Here we can see that the point x = 1 his mapped into two different values of y.

we have the pair (1, 2) and the pair (1, -3)

And something similar happens for x = 2.

Then we can conclude that this is not a function.

20) Here we have a linear relationship.

Linear relationships are almost always functions, the only case when these are not functions is when the linear equation is something like x = a.

Linear equations can be written as:

y = a*x + b

So x can be any value, and thus y also can be any value.

Then the domain is the set of all real numbers, and the range is the set of all real numbers.

24) Here we have a quadratic function whose arms go down.

This is a function, now let's see the domain and range.

Quadratic functions are written as:

y = a*x^2 + b*x + c

There is no value of x can cause some problem in this equation, then this function works for all values of x, then the domain is the set of all real numbers.

Now, let's look at the graph.

We can see that the function goes up, reaches a maximum, and then goes down again.

Then the range will be the set of all the values smaller than the maximum we can see in the graph, this is:

y ∈ (-∞, 15]

or simply:

y ≤ 15.

30) Here again, we can see that for x = 0 there are two different values of y.

the same happens for x = -1, x = -2, and a lot of other values.

Then this is not a function, because it is mapping values of the domain into different values of the range.

3 0
3 years ago
Help with my math READ IT CARFULLY
Irina-Kira [14]

Sci = π . 2 . 2 = 12,56 ⇒ 1/2 Sc1 = 1/2 . 12,56 = 6,28

Srec = 6 . 4 = 24

S= 6,28 + 24 = 30,28

the answer is 30,28

ok done. Thank to me :>

8 0
2 years ago
Solve for y.<br> 27=6x-9yx
slamgirl [31]

Answer:

Y= - 3/x+2/3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
3 years ago
What can you say about his average speed?
Nikitich [7]
The answer should be E. 223- 6s = 0
5 0
3 years ago
Other questions:
  • the scale for a map to actual distance is 2 cm to a 100 miles the actual distance on the map be between Los Angeles and Las Vega
    13·1 answer
  • The length of a rectangle is 4m more than the width.The area of the rectangle is 45 m^2.find the length
    9·1 answer
  • What the precents and decimals of these fraction 5/8. 66/200. 5 2/5. 2 7/16. has to be simplyed
    15·1 answer
  • E(t) models the daily amount of energy (in kilojoules, kJ) that a solar panel in Pago Pago generates, t days
    8·1 answer
  • Determine algebraically whether the function is even, odd, or neither. f(x = -5x2 4
    7·1 answer
  • 6m+2÷8=37 what does m=
    15·2 answers
  • 2 angles are complementary. One of the angles is 30 degrees. The other has a label of 5n + 20. What would "n" have to be?
    5·1 answer
  • Find the measure of angles a, b, c, d, and e. Only use numbers for your answers.
    6·2 answers
  • Solve for x.<br> Enter the solutions from least to greatest.<br> 2x^2– 5 = 13
    13·1 answer
  • PLEASEEEEEEEEEEEEEEEEEEEEEEEEE HELP MEEEEEEEEEEEEEEEEEEEEEEEE
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!