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saul85 [17]
3 years ago
6

A photo of a painting measured 13 x 17 inches the scale of the photo to the original painting is 1 inch to 3 inches. What is the

size of this painting
Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

  29 × 51 inches

Step-by-step explanation:

If the scale is ...

  photo : painting = 1 : 3

then each dimension of the painting is 3 times the corresponding dimension of the photo. The painting is (3×13) by (3×17) inches, or 39 × 51 inches.

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What dose a and x equal <br> 2³x 5- (√-1) a+ 5a - 3÷ x³
ser-zykov [4K]

The terms in which value of x when substituted leaves final value of p(x) = "0".

Here, x - 2 is factor. So value of x is 2.  

Substituting value of x we get,

p(x) = x3 - 3x + 5a

p(2) = 2*3 - 3(2) + 5a

0+ 8-6 + 5a

-2 = 5a

a= -0.4

Plz mark me as brainliest

7 0
3 years ago
8×1+5×(1/10)+9×(1/1,000)
dybincka [34]
8×1+5×(1/10)+9×(1/1000)
8+5×(.1)+9×(.001)
8+.5+.009
Answer is 8.509

7 0
3 years ago
An equal number of students from two Algebra 1 classes at Bozeman School were randomly selected and asked how many hours per wee
cricket20 [7]

Answer:

Largest Median: Same

Largest Range: Castro

Largest IQR: Castro

Step-by-step explanation:

With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.

Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both

Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.

Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8

6 0
3 years ago
A study indicates that 62% of students have have a laptop. You randomly sample 8 students. Find the probability that between 4 a
Scrat [10]

Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that n = 0.62

You randomly sample 8 students.

This means that n = 8

Find the probability that between 4 and 6 (including endpoints) have a laptop.

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157

P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815

P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

3 0
3 years ago
7 times a number is 8 less than the square of that number. Find the negative solution.
charle [14.2K]

Answer:

  -1

Step-by-step explanation:

The required relation is ...

  7n = n^2 -8

  0 = n^2 -7n -8 . . . . put in standard form

  0 = (n -8)(n +1) . . . . factor

Solutions are n=8 and n=-1.

The negative solution is -1.

7 0
3 years ago
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