We are given that the angle a is the right angle. So let us work from this.
ab = 12 (the vertical side of the triangle)
bc = 13 (which if drawn can be clearly observed to be the hypotenuse) = the side opposite to angle a
ca = 5 (the horizontal side of the triangle)
Since we are to find for the cosine ratio of angle c or angle θ, therefore:
cos θ = adjacent side / hypotenuse
cos θ = ca / bc
cos θ = 5 / 13
Check out the attached image below for the illustration of the triangle.
The image of circle A is missing, so i have attached it;
Answer:
x = 17
Step-by-step explanation:
In Δs EAB and EAD
We are told that;
∠BAE ≅ ∠DAE
AB = AD = AE
Now,
The Two triangles have two corresponding equal sides and the angles between them are equal, thus, we can say that the two triangles are congruent by SAS (Side Angle Side) postulate of congruence
By using the result of congruence, we can say that;
EB ≅ ED
We are given that;
EB = 3x - 24 and ED = x + 10
Thus,
3x - 24 = x + 10
∴ 3 x - 24 = x + 10
Add 24 to both sides to give;
3x = x + 34
Subtract x from both sides to give;
2x = 34
Divide both sides by 2 to give;
x = 17
