Answer:
1615
Step-by-step explanation:
Area of triangle is: A= B•H•1/2
Area of square is A= L•W
39•17•1/2= 331.5
331.5•4= 1326
17•17= 289
Add the square area to the area of the triangles
289+ 1326= 1615
hope this helps chu <3
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $470
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
Therefore, the equation used to determine the value of his bond after t years is
A = 470(1 + 0.06/1)^1 × t
A = 470(1.06)^t
Answer:
The y-intercept is at y = 10.
Step-by-step explanation:
It will be between y = 14 and y = 7 because the corresponding x values are -2 and 1.
An increase of 3 units of x gives a decrease of 6 units of y fro the above values.
Then an increase of 1 ( 1 to 2) in x gives decrease in y of 2 (8 to 6). The other values show the same pattern.
So very unit increase in x, the y values change by -2.
So from x = -2 to 0 is +2 units for x and this will be -4 units for y so the y-intercept ( when x = 0) will be at y = 14-4 = 10
y-intercept is (0,10).
Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with
rows and
columns is
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is
as it has 3 rows and 2 columns.
The order of matrix 3B is
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
Answer:
the equation is - 
Explanation:
Given -

We have to find a line passing through the point
nd parallel to the given line.
Find the slope of the given line.
It is the coefficeint of 
m₁ = 1
The two lines are parallel. Hence
m₂=m₁=1 Where m₂is the slope of the second line.
You have slope and the points 
Find the Y intercept

Y-Intercept
and slope m₂=1
Fix the equation
