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2 years ago

6 Résolvez les équations suivantes.

Mathematics

1 answer:

Degger [83]2 years ago

5 0

Step-by-step explanation:

a) x + 4 = 12

=> x + 4 - 4 = 12 - 4

=> x = 8

d) - 14 = 2x

=> -14/2 = 2x/2

=> -7 = x

x = -7

b) x + 5,1 = x + x

1 = x + x

1 = 2x

1/2 = 2x/2

x = 1/2 or 0.5

e) 5 = 4x

=> 5/4 = 4x/4

=> x = 5/4 or 0.8

c) 6x = x - 15

=> x - 15 = 6x

=> -15 = 6x - x

=> -15 = 5x

=> -15/5 = 5x/5

=> x = -3

f) x + 8 = 2x + 3

x+8=2x+3

x+8−2x=2x+3−2x

−x+8=3

−x+8−8=3−8

−x=−5

−x/−1 = −5/−1

x=5

J'espère que cela vous aidera, si vous avez d'autres problèmes, dites-le moi

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The solution to the problem is as follows:

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3 years ago

Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?

bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be $h(t) = -16t^2+150t+100$

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

$0 = -16t^2 + 150t + 100$

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

$t = \frac{-150 \pm \sqrt{150^2-4(-16)(100)}}{2(-16)}$

$t = \frac{-150 \pm \sqrt{22500+6400}}{-32}$

$t = \frac{-150 \pm \sqrt{28900}}{-32}$

$t = \frac{-150+170}{-32} = \frac{20}{-32} = -0.625$

time cannot be negative so we will drop this answer

then $t = \frac{-150-170}{-32} = \frac{-320}{-32} = 10$

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, $h = -16(0)^2+150(0)+100 = 100 feet$

For t =2 seconds, $h = -16(2)^2+150(2)+100 =336 feet$

For t =4 seconds, $h = -16(4)^2+150(4)+100 = 444 feet$

For t =6 seconds, $h = -16(6)^2+150(6)+100 = 424 feet$

For t =8 seconds, $h = -16(8)^2+150(8)+100 = 276 feet$

For t =10 seconds, $h = -16(10)^2+150(10)+100 = 0 feet$

(d) Axis of symmetry is given by formula

$x = \frac{-b}{2a}$

$t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875$

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

$x = \frac{-b}{2a}$

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, $h = -16(4.6875)^2+150(4.6875)+100 = 451.563$

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

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3 years ago

What is the answer 25b • (3a2 - 1)

Usimov [2.4K]

Answer:

Step-by-step explanation:

25b * (3a² - 1) = 25b * 3a² - 25b * 1

= 75ba² - 25b

Distributive law upon subtraction:

a(x - y) = ax - ay

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3 years ago