generate by: Amplitude:5 Period:4
Phase shift:(3 to the right) Vertical shift:-2
x=3,g(x)= 3
x=4,g(x)= -2
x=5,g(x)= -5
x=6,g(x)= -2
x=7,g(x)= 3
the graph is like cos(x)
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Please help me I’m so lost
2 answers:
The side length of the square is 2*((8/2)^.5) = 4cm
The area is 4^2 = 16 cm
See the attached picture. The parts labeled a and b are both the same length since this is a square. And each of them is half of the side length of the square. We can find the length of a and b using the Pythagorean theorem because the 8cm is a hypotenuse of a right triangle. So we find a, and multiply by 2 to get the square side length. Then we square that to get the square area.
The area is 4^2 = 16 cm
See the attached picture. The parts labeled a and b are both the same length since this is a square. And each of them is half of the side length of the square. We can find the length of a and b using the Pythagorean theorem because the 8cm is a hypotenuse of a right triangle. So we find a, and multiply by 2 to get the square side length. Then we square that to get the square area.
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