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3 years ago

Someone help me with this Alegerbratic expression. Really hard 10 questions.

Mathematics

1 answer:

Nady [450]3 years ago

7 0

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need help.. The midpoint of GH is M(-6,-3). One endpoint is H (-4,4) Find the coordinates of endpoint G.

iren2701 [21]

Answer:

The coordinates of G are: (-8, -10)

Step-by-step explanation:

Mid point formula:

$x = \dfrac{x_1+x_2}{2}\\y = \dfrac{y_1+y_2}{2}$

Where,

$(x,y)$ are the coordinates of the mid point of the points $(x_1,y_1)$ and $(x_2,y_2)$ .

As per question statement, we are given that:

$x_2=-4\\y_2=4$

and

$x=-6\\y=-3$

To find:

$x_1 = ?\\y_1 = ?$

Solution:

Let us use the mid point formula:

$-6 = \dfrac{x_1-4}{2}\\\Rightarrow -12=x_1-4\\\Rightarrow x_1=-12+4\\\Rightarrow \bold{x_1=-8}$

$-3 = \dfrac{y_1+4}{2}\\\Rightarrow -6=y_1+4\\\Rightarrow y_1=-6-4\\\Rightarrow \bold{y_1=-10}$

The coordinates of G are: (-8, -10)

5 0

3 years ago

Area model multiplication: 2x2 digits what to do forget how to do it

valkas [14]

Answer:

Step-by-step explanation:

Yes because

4 0

3 years ago

The diameter is 12 inches. What is the area? What do I do to solve it please help!

SashulF [63]

Answer:

113.04 sq. in.

Step-by-step explanation:

If the diameter of the circle is 12", then the radius is 6" (half the diameter), and the area "A" is (approximately) 3.14 * 6^2. The calculation is approximate because 3.14 is a rounded value for pi.

3 0

3 years ago

Read 2 more answers

Sally won 40 super bouncy balls playing horseshoes at her school's game night. Later, she gave two to each of her friends. She o

Aneli [31]

Answer: Sally has 16 friends

Step-by-step explanation:

she has 40 balls

subtract by how many she gave away

40-8=32

she gave 2 to each friend

divide the balls left by 2

32/2=16

Sally has 16 friends

4 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago