Mdndkddjntrhd hccjdjdj the dodo
Answer:
Step-by-step explanation:
1. no-has decimal
2. yes, simplifies to -2
3. yes
4. yes
5. no-2.1
Answer: x = -3/4 can not be a rational zero of the polynomial.
Step-by-step explanation:
We have the polynomial:
6x^5 + ax^3 -bx -12 = 0.
The theorem says that:
If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).
The factors of -12 (different than itself) are (independent of the sign).
1, 2, 3, 4 and 6.
So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.
The factors of 6 are:
1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.
Then the option that can not be a zero of the polynomial is
x = -3/4
because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.
There is no n just N
so for N will be
N = (9v -4f)/K
hope helped
Answer: The slope is 5.
Step-by-step explanation: Use formula: (y2-y1)/(x2-x1)
(7-2)/(4-3)
5/1 = 5
Have a nice day! :)
