3 years ago

I need to know this

Mathematics

1 answer:

kondor19780726 [428]3 years ago

8 0

Answer:

C. 26 to 29

She will need between 26 to 29 tables

Step-by-step explanation:

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Is the following relation a function? ху 1 -2 1-3 2 1 3 - 2 Yes No

professor190 [17]

Answer:

Step-by-step explanation:

In order to be a function you should have one output for every input (or one y for every x). In this case there are multiple outputs for the number one which means the relationship isn't a function

4 0

3 years ago

How do you solve these problems?

Rzqust [24]

A)

$\bf log_4(x)=3\\\\
-----------------------------\\\\
log_{{ a}}{{ a}}^x\implies x\qquad \qquad 
\boxed{{{ a}}^{log_{{ a}}x}=x}\impliedby 
\begin{array}{llll}
\textit{we'll use this}\\
\textit{cancellation rule}
\end{array}\\\\
-----------------------------\\\\
4^{\cfrac{}{}log_4(x)}=4^3\implies x=4^3$

b)

$\bf 3^{2y}=81\qquad 
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^{2y}=3^4\impliedby 
\begin{array}{llll}
\textit{same base}\\
exponents\\
must\ be\\
the\ same
\end{array}
\\\\\\
2y=4\implies y=\cfrac{4}{2}\implies y=2$

6 0

3 years ago

(30 points, will mark as brainliest) I need help with my algebra 1 homework, its open book so don't worry I can ask on here.

vichka [17]

Answer:

Step-by-step explanation:

y=kx

8=-4k

k=-2

so y=-2x

$eq.~of~line~is~y-4=\frac{4-4}{1+3} =\frac{0}{4} =0\\or~y=4\\or~y=0 x+4$