Answer:
C. 26 to 29
She will need between 26 to 29 tables
Step-by-step explanation:
4
Try this option:
1] P(S)=0.84;
2] P(S or C, but not both)=0.4;
3] P(C)=0.76;
4] P(S∪C)=0.6;
5] P(C, but not S)=0.16;
6] P(S∩C)=1.00.
whyd you post this thx 4 the points tho
