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Volgvan
3 years ago
5

For positive test result, the number of those who did not lie and lie are 11 and 41, respectively. Those of the negative test re

sult are 30 and 8. Find P(subject lied I negative results) and P(negative results I subject lied).
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

P(subject lied | negative results) = 4/19

P(negative results | subject lied) = 8/49

 

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

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Urgent please help..
storchak [24]
The answer is 51.3

Explanation:
You’re finding angle Y, so write the SOH CAH TOA. the two sides your are given are the adjacent side to Y and the opposite side so you use tangent. You then get the equation tanY=10/8 Since you’re finding an angle you use inverse tangent so you get y=tan^-1(10/8) and then put that into the calculator!
8 0
3 years ago
633 divided by 3 long division pls I'm doing a test 5th grade kk​
solong [7]

hi!!

here is your answer

Answer:

221

Step-by-step explanation:

when you divide 633 by 3, you will get 211

hope it helps you ❤❤❤

3 0
3 years ago
Jason sells tires and makes 15% commission. If he sold a total of $850 last week, how much commission will he earn?
Anastaziya [24]

Answer:

$127.5

Step-by-step explanation:

15% of $850 is 850 times .15 (% is decimal multiplied by 100)

850 * .15 = $127.50

6 0
3 years ago
In a box of chocolates, 1/5 of the chocolates contain nuts.
Rama09 [41]

Answer:

The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4

Step-by-step explanation:

The parameters given are;

Proportion of the box of chocolates that contain nuts = 1/5

Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5

Therefore, we have in a box of chocolates with five chocolates;

The number of chocolates that contain nuts = 1

The number of chocolates that do not contain nuts = 4

Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.

6 0
3 years ago
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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