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3241004551 [841]
3 years ago
15

Which is the lower left quadrant on the coordinate plane?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
5 0
QUADRANT III !!!!!!!
kari74 [83]3 years ago
4 0

Answer:

QUADRANT III

Step-by-step explanation:

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(02.01)
malfutka [58]

Answer:

the answer is Any Real Number

because  4(x + 1) = 4x + 4 for all value of x

Step-by-step explanation:

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It is vey hard and I’m honing
kobusy [5.1K]
Oh really? That’s tough bud
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What is the surface area of the figure?
Zielflug [23.3K]

Answer:

90 ft

Step-by-step explanation:

Times the length by the width of one side: 6 x 3= 18

Times 18 by 4 to get the surface area of the 4 rectangular sides: 18 x 4= 72

Times 3 by 3 to get the bottoms surface area: 9

Times 9 by 2 to get both the top and bottoms surface area: 18

Add 72+18 to get the total surface area: 90 ft

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Yep me plz I will mark
Anastaziya [24]

Answer:

v=125 cubic inches

Step-by-step explanation:

V=s^3

s=5

V=5x5x5

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3 years ago
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A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classe
stealth61 [152]

Answer:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

Step-by-step explanation:

Information given

\bar X_{1}=4 represent the mean for sample A

\bar X_{2}=3.5 represent the mean for sample B

s_{1}=1.5 represent the sample standard deviation for A

s_{2}=1 represent the sample standard deviation for B  

n_{1}=11 sample size for the group A

n_{2}=9 sample size for the group B  

\alpha=0.1 Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2} \leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=11+9-2=18  

Replacing we got:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

5 0
3 years ago
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