Answer:
∠1 + ∠2 + ∠3 = 180°
Step-by-step explanation:
Given : AB II XC
To Show : ∠1 + ∠2 + ∠3 = 180°
Proof: Here, given that AB is parallel to the line XC
⇒ ∠4 = ∠2 (Pair of Alternate angles as AB II XC) ......... (1)
and ∠5 = ∠3 (Pair of Alternate angles as AB II XC) ........... (2)
Now, ∠1 + ∠4 + ∠5 = 180° ( Straight Angle)
But, from above (1) and (2)
∠1 + ∠2 + ∠3 = 180° ( as ∠4 = ∠2, ∠5 = ∠3)
Hence, ∠1 + ∠2 + ∠3 = 180°
Hence Proved.
Answer:
ft if
Step-by-step explanation:
good morning I am not sure if you have received this email is strictly confidential and may be a good time
Answer:
like with the whole page?? cause if so i got this KINDA
Step-by-step explanation:
the first one (2/9+2/9) = 4/9
the second one (1/4+2/4)=3/4
the third one (3/8+5/8)=1 whole or 8/8
i cant see the last one so ill skip to the bottom row
the first one (2/5-1/5)=1/5
(9/12-4/12)=5/12
(4/10-2/10)= 2/10
and ill give someone else a shot with the rest of the questions but yw
this is pretty simple but hit me up if you ever need more help
=D
Answer:
See below.
Step-by-step explanation:
Base case:
Replace n with 1.
7^(2×1+1)+1
7^3+1
343+1
344
8 is a factor of 344 since 344=8(43).
Induction hypothesis:
Assume there is some integer n such that 7^(2k+1)+1=8n for positive integer k.
7^(2[k+1]+1)+1
7^(2k+3)+1
7^(2k+1+2)+1
7^(2k+1)7^2+1
49×7^(2k+1)+1
Induction step:
49×(8n-1)+1
49(8n)-49+1
49(8n)-48
8[49n-6]
This means 8 is a factor of 7^(2(k+1)+1)+1.
Thus, this proves for all positive integer n that 8 is a factor of 7^(2n+1)+1.
Answer:
x=4 hope this helps
Step-by-step explanation:
