Question

Acceleration: A driver is traveling eastward on

Answer 1

Answer:

$-1.42 m/s^2$ is the car's acceleration.

Explanation:

Initial velocity of the driver = u = 14 m/s

Final velocity of the driver = v = 5.5 m/s

Duration of time in which 14 m/s velocity is changed to 5.5 m/s = t = 6.0 s

Acceleration of the driver = a

Using first equation of motion: v = u + at

$5.5 m/s=14 m/s+a\times (6.0 s)$

$5.5 m/s-14m/s =a\times 6.0 s$

$-8.5 m/s=a\times 6.0 s$

$a=\frac{-8.5 m/s}{6.0 s}=-1.417 m/s^2\approx -1.42 m/s^2$

Negative sign indicates the that is deceleration is occurring that is speed of the car is decreasing.