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3 years ago

Factor the trinomial. x^2-4x-5

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

<h3>Answer: Choice C. (x+1)(x-5)</h3>

We need to find two numbers that

Multiply to -5 (last term)
Add to -4 (middle coefficient)

Through trial and error, those two numbers are 1 and -5

1 times -5 = -5
1 plus -5 = -4

So this means x^2-4x-5 factors to (x+1)(x-5)

This is the same as (x-5)(x+1) since the order of multiplication doesn't matter.

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Pls help with asap thxxu! :)

Stella [2.4K]

Answer:

C- Equilateral triangle

Step-by-step explanation:

I am not very sure dear

7 0

3 years ago

Read 2 more answers

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago

the size of the second application is 3.45 MB less than he first application. What is the size of the second application

mr_godi [17]

The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

<h3>Equation</h3>

Let

Size of the first application = x

Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

= 293.55 MB

Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB

Learn more about equation:

brainly.com/question/2972832

#SPJ1

6 0

1 year ago

Solve the following equation: x÷3-5=-7

Elodia [21]

Answer:

- 6

Step-by-step explanation:

Step 1:

x ÷ 3 - 5 = - 7 Equation

Step 2:

x ÷ 3 = - 2 Add 5 on both sides

Answer:

x = - 6 Multiply 3 on both sides

Hope This Helps :)

3 0

2 years ago

Lesson Check (4.MD.C.7)

vredina [299]

The measure of Zx is 4

8 0

3 years ago