Help me please !!!!!!!

In a kitchen there are three containers that can hold different quantities of water, as shown in the figure below:

ch4aika [34]

Answer:

A) 3x

Step-by-step explanation:

The total of all the volumes is ...

(x -1) + (x) + (x +1) = (1+1+1)x +(-1+1) = 3x+0 = 3x . . . . . matches choice A

6 0

3 years ago

I need the answer with work

Alenkasestr [34]

1. Regroup terms
x^3 - 6 * 10x^2x-8/ x-3
2. Use product rule
x^3 - 6 * 10x^ 2+1 - 8/ x-3
3. Simplify
x^3 - 6 * 10 x^3 - 8/ x-3
4. Simplify further
x^3 - 60x^3 - 8/ x-3
5. Simplify the last time
-59x^3-8/x-3

3 0

3 years ago

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago

The captain of a boat knows that a lighthouse on the coast is 100 ft. tall. If he measures the angle of elevation to be 2 degree

faltersainse [42]

Answer and Step-by-step explanation:

| \

| \

100 ft. | \

| 2 \

|_________\

x

Use tangent to find the x.

tan(2) = $\frac{100}{x}$

$x = \frac{100}{tan(2)}$

Use a calculator to evaluate.

$x = \frac{100}{tan(2)}$ = 2863.6253

So, the boat is 2,863.63 feet from the shore.

#teamtrees #WAP (Water And Plant)

6 0

3 years ago

Emir is standing in a treehouse and looking down at a swingset in the yard next door. The angle of depression from Emir's eyelin

boyakko [2]

<h3>Answer: 24 feet (Choice D)</h3>

=============================================

Explanation:

Refer to the diagram below. The goal is to find x, which is the horizontal distance from the base of the tree to the swing set.

Focus on triangle BCD.

The angle B is roughly 30.26 degrees, and this is the angle of depression. This is the amount of degrees Emir must look down (when starting at the horizontal) to spot the swing set.

We know that he's 14 ft off the ground, which explains why AB = CD = 14.

The goal is to find BC = AD = x.

---------------------------

Again, keep your focus on triangle BCD.

We'll use the tangent ratio to say

tan(angle) = opposite/adjacent

tan(B) = CD/BC

tan(30.26) = 14/x

x*tan(30.26) = 14

x = 14/tan(30.26)

x = 23.9965714046732

That value is approximate. Make sure your calculator is in degree mode.

That value rounds to 24 feet when rounding to the nearest whole foot.

6 0

3 years ago