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3 years ago

The mass of a penny was measured six times. The following data was reported:

Mathematics

1 answer:

Scrat [10]3 years ago

4 0

Answer:

a) 8.103 g

b) 9.2948

c) 0

Step-by-step explanation:

Given:

Data reported:

9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 g

Now,

All the values except the 8.103 are above 9

Here the data 8.103 varies very much with respect to the other values

Hence,

a) the data 8.103 should be excluded

b) average value of the mass of the penny = $\frac{9.314 + 9.215 + 9.323 + 9.278 + 9.344 }{5}$

= 9.2948 g

c) Deviation = Mean - Data

9.2948 - 9.314 = -0.0192

9.2948 - 9.215 = 0.0798

9.2948 - 9.323 = -0.0282

9.2948 - 9.278 = 0.0168

9.2948 - 9.344 = -0.0492

Thus,

Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]

= 0

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vladimir1956 [14]

Answer:

Step-by-step explanation:

sin 44° = $\frac{63}{ST}$

ST = $\frac{63}{sin44}$

ST ≈ 90.7

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2 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

2x-2y=-6

7x =-21

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

2 years ago

100m world record was completed at an average speed of 37.6 km/h. work out this speed in meters per second?

pickupchik [31]

Step-by-step explanation:

1 km = 1000 m

1 hour = 3600 s

so,

37.6 km = 37,600 m (still per hour or per 3600 s).

in 1 second now that is

37600/3600 = 10.44444444... m/s

4 0

1 year ago

What are the real zeros of the function g(x) = x3 + 2x2 − x − 2?

Nat2105 [25]

Upon a slight rearrangement this problem gets a lot simpler to see.

x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...

x(x^2-1)+2(x^2-1)=0

(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:

(a^2-b^2) which always factors to (a+b)(a-b), in this case:

(x+2)(x+1)(x-1)=0

So g(x) has three real zero when x={-2, -1, 1}

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2 years ago

For a left-tailed test, the critical value of z so that a hypothesis test would reject the null hypothesis at 1% significance le

mars1129 [50]

Answer:

C.-2.33

Step-by-step explanation:

We are given that

Significance level, $\alpha =1$ %=0.01

We have to find the critical value of z for a left-tailed test.

To find the critical value , we will use the z-table at significance level 0.01 for left-tailed test.

By using the z-table at significance level 0.01 for left-tailed test

The critical value of z at 1% significance level for left-tailed test

=-2.33

We get p-value by using z-critical value

P-value=0.0099<0.01

So, hypothesis test would be reject the null hypothesis at at 1% significance level.

Hence, the critical value of z=-2.33

Option C is true.

8 0

2 years ago