Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer: Ik an easier way to answer it without waiting for someone to answer it for you. So all you have to do is search up the question for each expression and you'll find it. I remember doing this yesterday for nearly that exact worksheet but i forget the answers and cant go back so im just telling you how to find the answers your welcome
Step-by-step explanation:
Answer:32
Step-by-step explanation:
Answer:
yes the answer is the answer that you need lol thx
hope it helped :)
Step-by-step explanation: