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kirza4 [7]
3 years ago
14

A coin is flipped 18 times. Three of the times the coin landed on heads and the rest of the times tails. What is the difference

between the THEORETICAL and EXPERIMENTAL probability of landing on heads? *
Mathematics
1 answer:
stira [4]3 years ago
3 0

Answer:

the experimental probability is based on the results of the experiment which yielded heads 1 out of 6 times; in theory, the results of flipping a coin and landing on heads would be 1 out of 2

Step-by-step explanation:

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Lorico [155]
The square on the hypotenuse is skew and impossible to visually validate. There's nothing to sum. It is a simple calculation to note that <span><span><span>32</span>+<span>42</span>=<span>52</span></span><span><span>32</span>+<span>42</span>=<span>52</span></span></span><span>, but its picture doesn't 'say' that the angle between the 3 and 4 sided square must be 90 degrees.


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7 0
3 years ago
Brielle and Joshua are running a half marathon race, which is
Salsk061 [2.6K]

Answer and Explanation:

Brielle will run the marathon faster.

Work:

Brielle: 13.1/1.25=10.48*10=104.8 minutes

Joshua: 13.1/1.5=8.73...*18=157.2 minutes

Brielle finished in 104.8 minutes.

Joshua finished in 157.2 minutes.

Brielle finished the half marathon race by 52.5 minutes faster than Joshua.

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7 0
3 years ago
Help, I don’t understand
Agata [3.3K]

Answer: -1

Step-by-step explanation: f(x) is another way of saying y. So when y is 3, according to the table, x is -1

3 0
3 years ago
A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength
irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

<u><em>Let </em></u>\bar X<u><em> = sample mean comprehensive strength</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean comprehensive strength = 5500 psi

            \sigma = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(\bar X > 4985 psi)

    P(\bar X > 4985 psi) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{4985-5500}{\frac{100}{\sqrt{9} } } ) = P(Z > -15.45) = P(Z < 15.45)

                                                                  = <u>0.99999</u>

<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>

4 0
4 years ago
The probability that a new advertising campaign will increase sales is assessed as being 0.80. The probability that the cost of
tatuchka [14]

Answer:

The probability that the cost is kept within budget or the campaign will increase sales is 0.88

Step-by-step explanation:

The probability that the cost is kept within budget (event A) <u>or</u> the campaign will increase sales (event B) is the <u>union</u> of the probability of those two events. By basic properties of probability, this is:

P(A ∪ B) = P(A) + P (B) - P(A ∩ B)

and for independent events:

P(A ∩ B) = P(A) * P(B)

So:

P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88

5 0
3 years ago
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