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11Alexandr11 [23.1K]
3 years ago
14

The weight of a product is normally distributed with a mean of four ounces and a variance of .25 "squared ounces." The company w

ants to classify the unit as a scrap in a maximum of 1% of the units if the weight is below a desired value. Determine the desired weight such that no more than 1% of the units are below it.

Mathematics
1 answer:
pychu [463]3 years ago
8 0

Answer:

Weight=2.835

Step-by-step explanation:

See the attached picture for explanation.

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A store has clearance items that have been marked down by 30%. They are having a sale, advertising an additional 60% off clearan
Schach [20]

Answer:

28%

Step-by-step explanation:

We get 30% off the original price

The new price is (100-30) = 70$ of the original price

Let x = the original price

The new price is .7x

Now get get an additional 60% off.  We pay (100-60) = 40 percent of the price

Take .7x * .4

The new price is .7*.4 x

                               .28x

This is 28 percent of the original price x

8 0
3 years ago
A dollar bill is about 0.00011 meter thick. What is this thickness in scientific notation?​
inn [45]

Answer:

1.1×10^-4

Step-by-step explanation:

we move the point from where to in between 1.1 and counts the number of numbers it has crossed..in this case it 4...which should be -4

6 0
3 years ago
A bag contains 3 red, 5 yellow, and 7 purple marbles. Find the probability of drawing a purple marble followed by a red marble.
jeka57 [31]

Answer:

unsimplified : \frac{21}{225} or simplified: \: \frac{7}{75}

Step-by-step explanation:

Work out : Look above at image.

3 0
3 years ago
The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?
Stella [2.4K]

Answer:

x = 5, 2

Step-by-step explanation:

x^2 = 7x - 10

x^2 -7x + 10 = 0

(x - 2)(x - 5) = 0

x = 5, 2

7 0
3 years ago
The expression (secx + tanx)2 is the same as _____.
trapecia [35]

<u>Answer:</u>

The expression \bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}

<u>Solution:</u>

From question, given that \bold{(\sec x+\tan x)^{2}}

By using the trigonometric identity (a + b)^{2} = a^{2} + 2ab + b^{2} the above equation becomes,

(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x

We know that \sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}

(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}

=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}

On simplication we get

=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}

By using the trigonometric identity \cos ^{2} x=1-\sin ^{2} x ,the above equation becomes

=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}

By using the trigonometric identity (a+b)^{2}=a^{2}+2ab+b^{2}

we get 1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}

=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}

=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}

By using the trigonometric identity a^{2}-b^{2}=(a+b)(a-b)  we get 1-\sin ^{2} x=(1+\sin x)(1-\sin x)

=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}

= \frac{1+\sin x}{1-\sin x}

Hence the expression \bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}

8 0
3 years ago
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