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forsale [732]
4 years ago
8

2•2•2•2•2•3•3•3•3 in exponential form.

Mathematics
2 answers:
pentagon [3]4 years ago
8 0

Answer:

2^5 and 3^4

Step-by-step explanation:

you can see there are 5 2's and 4 3's. so it would be 2^5 and 3^4

Fantom [35]4 years ago
6 0
OK so the dots mean times so you can do 2x2x2x2x2x3x3x3x3 or you can do 2 with the number 5 on the corner x 3 with a 4 on the corner
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Area= 60

Step-by-step explanation:


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You must use the substitution method. 3x+2y=11 <br> y=5x-1
valina [46]
Plug in y=5x-1 for y in 3x+2y=11

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5 0
4 years ago
For this problem you have to solve for m
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8 0
3 years ago
Read 2 more answers
Help please
ddd [48]
Length of the box = 25 - 2x
Width of the box = 14 - 2x
Height of the box = x

a.) Volume of the box = x(25 - 2x)(14 - 2x) = x(350 - 50x - 28x + 4x^2) = 4x^3 - 78x^2 + 350x
Therefore, the function that models the volume of the box is V(x) = 4x^3 - 78x^2 + 350x

b.) 4x^3 - 78x^2 + 350x ≥ 240
4x^3 - 78x + 350x - 240 ≥ 0
x = 0.834, 5.438
The values of x for which the volume is greater than 240 in^3 is 0.834 ≤ x ≤ 5.438

c.) For maximum volume, dV/dx = 0
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x = 2.882910931

Therefore, maximum volume = 4(2.882910931)^3 - 78(2.882910931)^2 +350(2.882910931) = 453.798 in^3
8 0
4 years ago
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