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antoniya [11.8K]
3 years ago
14

Mariain buys a dress that costs 32 dollars she pays 10 percent sales tax

Mathematics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

the total cost would be $45.2

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I need help with this
Debora [2.8K]
C because if you look at the intercept it’s a y and the y inception is equivalent to 4 so y=4x-14
5 0
3 years ago
1 1/4 as a improper fraction ​
ludmilkaskok [199]
That would be
5/4
.
Explanation:
This answer is valid because, when you multiply
4
×
1
, you get
4
. Then add one and keep the denominator, you will get
5
4
.
1
1
4
=
1
×
4
+
1
4
=
5
4
When you simplify
5
4
, you will get
1
1
4
Have a great day!
8 0
3 years ago
Read 2 more answers
Explain why all linear angle pairs must be supplementary, but all supplementary angles do not have to be linear pairs?
dimulka [17.4K]
Two angles are supplementary if their measures sum 180°.

Linear angle pairs are adjacent angles (they are together) and they form a straight angle, which is 180°. Therefore, they are supplementary.

But two angles may be separated and yet add 180°, then they are supplementary but are not linear angle pairs.
4 0
3 years ago
The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

Where

(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

k = constant

From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time t = 1 \ hour, T_{(t)} = 58^{o}C

Then, we can write that

T_{(1)}=58 = -20+106 e^{k(1)}

Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

First collect like terms

58 +20 = 106 e^{k}

78 =106 e^{k}

Then,

e^{k} = \frac{78}{106}

e^{k} = 0.735849

Now, take the natural log of both sides

ln(e^{k}) =ln( 0.735849)

k = -0.30673

This is the value of the constant k

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at t = 2 \ hours

From

T_{(t)}=-20+106 e^{kt}

Then

T_{(2)}=-20+106 e^{(-0.30673 \times 2)}

T_{(2)}=-20+106 e^{-0.61346}

T_{(2)}=-20+106\times 0.5414741237

T_{(2)}=-20+57.396257

T_{(2)}=37.396257 \ ^{o}C

T_{(2)} \approxeq  37.40 \ ^{o}C

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0
2 years ago
Read 2 more answers
Find the distance between the points with the given coordinates (-2, -5) and (-2, 4).
bija089 [108]
I hope this helps you

6 0
3 years ago
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