The only point which is a solution is C
The answer is
q + d = 12
0.25q + 0.10d = 2.40
q - the number of quarters
d - the number of dimes
You have 12 <span>coins, all quarters and dimes:
q + d = 12
The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40
Get the derivative:
<em>y</em> = (9 - <em>x</em>²)¹ʹ³
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ d/d<em>x</em> [9 - <em>x</em>²]
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ (-2<em>x</em>)
d<em>y</em>/d<em>x</em> = -2/3 <em>x</em> (9 - <em>x</em>²)⁻²ʹ³
Evaluate it at <em>x</em> = 1 :
d<em>y</em>/d<em>x</em> (1) = -2/3 • 8⁻²ʹ³
Since 8 = 2³, we have
8⁻²ʹ³ = 1 / 8²ʹ³ = 1 / (2³)²ʹ³ = 1 / 2² = 1/4
Then the tangent line has equation
<em>y</em> - 2 = 1/4 (<em>x</em> - 1) → <em>y</em> = 1/4 <em>x</em> + 7/4
Answer:
Step-by-step explanation:
There are 3 possibilities for the graph as shown in the figure.
(a) having zero intersection
(b) having one intersection point (touching point)
(c) having two intersection points.
So, the greatest possible number of intersections for these graphs is 2 as shown in figure (c).
Y=-4x+5 I believe you just rewrite the equation like this