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4 years ago

N is an integer, write down the values of n such that -15<3n<6

Mathematics

1 answer:

Ira Lisetskai [31]4 years ago

3 0

-15 < 3n < 6

Divide all sides by 3

-5 < n < 2

Now you need all integers between -5 and 2.

-4, -3, -2, -1, 0, 1

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Estimate V130 to the nearest integer.

erma4kov [3.2K]

Answer:

$\large\boxed{\sqrt{130}\approx11}$

Step-by-step explanation:

$\sqrt{a}=b\iff b^2=a\\\\11$

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3 years ago

allison uses 3 out of 5 of a bag of suger to bake 4 small cakes.what fraction of a bag of sugar was used in each cake?

Andrej [43]

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Answer: 3/5

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4 years ago

A shirt has an original price of $19.75. If the shirt is marked 25% off and there is a 7.75% tax, how

Bumek [7]

Answer: 4.90 im not 100 percent sure

Step-by-step explanation:

To find the actual discount, multiply the discount rate by the original amount 'x'. To find the sale price, subtract the actual discount from the original amount 'x' and equate this to given sale price.

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3 years ago

Read 2 more answers

Yeah I don’t get this

umka2103 [35]

using pythagorean theorem

a^2 + b^2 = c^2

(12x)^2 + (16x)^2 = 10^2

square each term

144x^2 + 256x^2 = 100

combine like terms

400 x^2 = 100

divide by 400 on each side

x^2 = 1/4

take the square root on each side

x = 1/2

Answer: x=1/2

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3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago