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2 years ago

14

Triangle X Y Z is shown. Angle Z W X is a right angle. An altitude is drawn from point W to point Y on side Z X to form a right

angle. The length of W Y is 4, the length of Y X is a, the length of Z Y is 3, the length of Z W is c, and the length of W X is b. What is the value of c? 4 units 5 units 6 units 7 units

2 answers:

ohaa [14]2 years ago

7 0

Answer:

b 5 units

Step-by-step explanation:

RUDIKE [14]2 years ago

6 0

Answer:

is there a picture?

Step-by-step explanation:

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How many times does 63 go into 7

Anna [14]

63 goes into 7, 9 times

8 0

3 years ago

Surface area of a rectangular prism if W = 6in L = 9in and H = 2in

Delicious77 [7]

Answer:

Step-by-step explanation:

Two faces are 6” by 9”. Two faces are 6” by 2”. Two faces are 9” by 2”.

Surface are = 2*6*9 + 2*6*2 + 2*9*2 = 108 + 24 + 36 = 168 square inches

4 0

3 years ago

-4/9 + (-1/3) ? Helppppp

Alex

Answer:

- 7/9

Step-by-step explanation:

-4/9 + (-1/3)

= -(4/9) - (1/3)

= - (4/9 + 1/3)

= - (4/9 + 3/9)

= - [(4 + 3) / 9 ]

= - 7/9

5 0

2 years ago

Quadrilateral ABCD is a rectangle. BD = 6x - 14 and AC = 8x - 20. What is BD?

BigorU [14]

Answer:

4

Step-by-step explanation:

The diagonals are equal length:

$6x - 14 = 8x - 20\\-2x = -6\\x = 3$

$BD = 6x - 14\\BD = 6 * 3 - 14\\BD = 18 - 14\\BD = 4$

8 0

2 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

2 years ago