A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o

Question

3 years ago

12

A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o

f the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Mathematics

2 answers:

deff fn [24] · Answer 1 · 2022-02-10T21:16:50+03:00

deff fn [24]3 years ago

7 0

Answer:

$0.2$ %

Step-by-step explanation:

Chance of missing the first shot is $0.4\\$

Chance of missing the second shot, when the first shot is missed is $0.05\\$

The probability of missing both free-throw shots

$= (0.4) (0.05)\\= 0.002\\= 0.2$ %

Semenov [28] · Answer 2 · 2022-02-10T19:27:56+03:00

Semenov [28]3 years ago

3 0

This can easily be answered. Justg use the next formula like this:
<span>0.4*0.05 = 0.02
</span>So the probability would be of 2% of both shots
Hpe this is very useful