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scoray [572]
3 years ago
12

A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o

f the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
2 answers:
deff fn [24]3 years ago
7 0

Answer:

0.2 %

Step-by-step explanation:

Chance of missing the first shot is 0.4\\

Chance of missing the second shot, when the first shot is missed is 0.05\\

The probability of missing both free-throw shots

= (0.4) (0.05)\\= 0.002\\= 0.2 %

Semenov [28]3 years ago
3 0
This can easily be answered. Justg use the next formula like this:
<span>0.4*0.05 = 0.02 
</span>So the probability would be of 2% of both shots
Hpe this is very useful
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4 years ago
F(x) = 1/x<br> g(x) = x - 4<br> Can you evaluate (gof)(0)? Explain why or why<br> not.
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<em><u>Solution:</u></em>

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