3 years ago

Solve for y2. d = y2- y1

1 answer:

8 0

D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.

D+y1=y2 that drops -y1 for the right side but the left remains.

And that's your answer.

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Step-by-step explanation:

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3 years ago

Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)

Nookie1986 [14]

Answer:

Step-by-step explanation:

The given formula is

$A=p(1+rt)$

Where $A=27$ and $t=3$

To solve for $r$ , first we need to move $p$

$\frac{A}{p}=1+rt$

Then, we move the term 1

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$\frac{\frac{A}{p}-1 }{t} =r$

Replacing given values, we have

$\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}$

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Step-by-step explanation:

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3 years ago

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ira [324]

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3 years ago

V^2+2=8-4v^2 solve the question algebically

iris [78.8K]

Answer:

v = ± sqrt(6/5)

Step-by-step explanation:

v^2+2=8-4v^2

Add 4v^2 to each side

v^2+ 4v^2+2=8-4v^2+ 4v^2

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Subtract 2 from each side

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Divide each side by 5

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Take the square root of each side

sqrt(v^2) = ± sqrt(6/5)

v = ± sqrt(6/5)

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3 years ago

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