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3 years ago

Help this is hard and I will thank you

Mathematics

1 answer:

Basile [38]3 years ago

7 0

F= G(m1m2/d^2)

First divide all terms by G

G(m1m2/d^2) / G = F/G

Cancel common Factor:

m1m2 / d^2 = F/G

Multipl;y both sides by d^2:

m1m2 = F/G * d^2

Divide both sides by m2:

m1 = F /G * d^2 /m2

Simplify:

m1 = Fd^2/Gm2

You might be interested in

State one rational number between -0.45 and -0.46 (answer must be in decimal form.)

seraphim [82]

A rational number between the two given ones is -0.455, such that:

-0.45 > -0.455 > -0.46

<h3>How to find a rational number between the two given ones?</h3>

A rational number is any number that can be written as a quotient between two integer numbers.

Particularly, any number with a finite number of digits after the decimal point is also a rational number.

So to find a rational number between -0.45 and -0.46 we could se:

-0.455, such that:

-0.45 > -0.455 > -0.46

Learn more about rational numbers:

brainly.com/question/12088221

#SPJ1

6 0

1 year ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago

Which of the following could be true if y ≤ -75?

Charra [1.4K]

Answer:-74

Step-by-step explanation: When you are in the megatives, less is more! So -74 is actually greater then -75

6 0

3 years ago

Ann is using a recipe that serves 20 people. the recipe requires 1/2 of a cup of sugar. how many cups of sugar does ann beed to

Setler [38]

Answer:

1 1/4 cup

Step-by-step explanation:

4 0

2 years ago

Show work please<br> 14 days = ______________ seconds<br><br><br> 1 year = ______________ minutes

zvonat [6]

Answer:

1.21e+6 seconds

525,600 minutes

Step-by-step explanation:

Seconds in 1 day: 86,400

Seconds in 14 days: 1.21e+6

multiply the time value by 86400

525600

multiply the time value by 525600

8 0

2 years ago