we know that
m∠SQR+x=
-------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR+
+
=
m∠SQR=
degrees
<u>Find the value of x</u>
m∠SQR=
x=-m∠SQR
x=
x=
degrees
therefore
<u>the answer is</u>
the value of x is degrees
4/(x+1) = 3/x + 1/15
Should we make common denominators with everything, we get
4*15*x / [15x(x+1)] = 3*15*(x+1)/[15x(x+1)] + x(x+1)/[15x(x+1)]
Multiply both sides of the equation by the denominator to cancel them
60x = 45(x+1) + x(x+1)
60x = 45x + 45 + x^2 + x
x^2 - 14x + 45 = 0
(x-9)(x-5) = 0
The answer to this question is that the solutions are x=9 and x=5.
This theorem says that the exterior angle is equal to the sum of its remote interior angles. In other words, 140 = 2x + x + 2. 140 = 3x + 2 and 138 = 3x. Therefore, x = 46. Multiply it by 2 to get angle B is 92 degrees.
5,25-5,58=0,33
The answer is $0,33
6n=11c=-8j+5
Just combine the terms!
