Answer:
A. square root of a^2 + b^2 for both answers
Step-by-step explanation:
The first problem, we are given
a^2 + b^2 = c^2
What we do is solve for c.
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
For problem 2,
WE can apply the Pythagorean theorem because we have a right triangle.
The equations is
a^2 + b^2 = c^2 like the first problem
Solving gets us
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
For x intercepts, plug in 0 for y.
0 = (x^2) - 2x - 35
*factoring* = (x-7)(x+5)
x intercepts = 7,-5
As for the vertex, you can use the equation -b/2a for the x-coordinate of the vertex
so,
x = -b/2a = -(-2)/2 = 1
then just find the y value by plugging it back in to the equation.
y = ((1)^2) - 2(1) - 35
= -36
so, vertex is at (1,-36)
A LmN > ; mqp by sas is the right answer
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
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