The derivative of
is
.
In this exercise we must apply the definition of derivative, which is described below:
(1)
If we know that
, then the derivative of the expression is:
![f'(x) = \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%20%5Clim_%7Bh%20%5Cto%200%7D%20%5Cfrac%7B2%5Ccdot%20%28x%2Bh%29%5E%7B2%7D-9-2%5Ccdot%20x%5E%7B2%7D%2B9%7D%7Bh%7D)
![f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%202%5Ccdot%20%5Clim_%7Bh%20%5Cto%200%7D%20%5Cfrac%7Bx%5E%7B2%7D%2B2%5Ccdot%20h%5Ccdot%20x%20%2B%20h%5E%7B2%7D-2%5Ccdot%20x%5E%7B2%7D%7D%7Bh%7D)
![f'(x) = 2\cdot \lim_{h \to 0} 2\cdot x + h](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%202%5Ccdot%20%20%5Clim_%7Bh%20%5Cto%200%7D%202%5Ccdot%20x%20%2B%20h)
![f'(x) = 4\cdot x](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%204%5Ccdot%20x)
The derivative of
is
.
We kindly invite to check this question on derivatives: brainly.com/question/23847661
Answer:
E=MC squared, the greater the mass the more momentum it generates and therefore, more energy
Answer:
90 men
Step-by-step explanation:
just keep the ratio constant
3:7
equals 10 parts
300/10=30
3*30:7*30
90 men and 210 women
hope this helps!!! :)
The given equations are;
2x-y=8......(i)
3x+y=17......(ii)
Adding equation (i) and (ii), we get
5x=25 ( as +y and -y is canceled out during addition)
Hence x=5
Now
Substituting the value of x in equation (i)
2x5-y=8
10-y=8
Hence y=2