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Zigmanuir [339]
3 years ago
12

Pablo created the bar model and equation after paying a $9.78 Lunch bill with a $20 bill what is the value of c, and what does i

t represent in this problem
Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0

Answer:

C he revived 10.21

Step-by-step explanation:

Iteru [2.4K]3 years ago
5 0

What are the options for you to choose? This would help answer faster

You might be interested in
Can someone help me please ? Thanks!
notka56 [123]
Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right 

b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute

c. 64+81=144
145>144
acute

hope this helps!
6 0
3 years ago
Read 2 more answers
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Why might you complete a 1040 instead of a 1040EZ?
Katyanochek1 [597]
<span>Your taxable income must be less than $100,000 and only come in the form of wages</span>
6 0
4 years ago
I need help with 5 thanks
Mars2501 [29]

For every 3 cups of peanuts there are 2 cups of chocolate

9/3 = 3 so 3*2 = 6

For 9 cups of peanuts there are 6 cups of choclate

3 0
4 years ago
Please help asap. I will give brainiest.
nirvana33 [79]

A that is the answer

5 0
3 years ago
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