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yKpoI14uk [10]
3 years ago
14

Need help with these proofs.

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Step-by-step explanation:

it is proved in above figure

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​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
Sheryl is making 4 equal servings from a recipe that contains 84 calories. Which equation could Sheryl use to find the number of
Makovka662 [10]
The answer is 84 divided by 4=c
8 0
3 years ago
Solve the equation
Klio2033 [76]

Answer:

x = 25

Step-by-step explanation:

.20x + .68(120 - x) = .54(120) (Distribute .68 to 120 and -x)

.20x + 81.6 - .68x = .54(120) (multiply .54 and 120)

.20x + 81.6 - .68x = 69.6 ( add .20x and -.68x)

-.48x + 81.6 = 69.6 ( subtract 81.6 on each side)

-.48x = -12 (divide -12 by -.48)

x = 25

4 0
3 years ago
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
6. Circle all the expressions that are equivalent to this expression: 6p+ 7.
-BARSIC- [3]
Number 4 and 6 are correct because you can only add variables with other variables so that is why 4 and 6 are correct
8 0
3 years ago
Read 2 more answers
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