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Alex777 [14]
3 years ago
8

1

Computers and Technology
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

A

Explanation:

.

.stack 4096

ExitProcess PROTO, dwExitCode:DWORD

.data

Sun=0

Mon=1

Tue=2

Wed=3

Thu=4

Fri=5

Sat=6

warray BYTE Sun, Mon, Tue, Wed, Thu, Fri, Sat

INVOKE ExitProcess, 0

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Explanation: Hope this helps

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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

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   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

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   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

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