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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

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3 years ago

Which early modernism trend in art focused on prehistoric or exotic cultures? primitivism expressionism impressionism total seri

AleksAgata [21]

Actually it's Primitivism

3 0

3 years ago

0.0% complete question a forensics analyst is attempting a live acquisition of the contents of the memory of a running linux dev

Sonja [21]

Based on the question, the Recommendation of a framework that will enable the analyst to install a kernel driver is said to be Volatility.

<h3>What is the Volatility framework?</h3>

Volatility is said to be a kind of an open source framework that is known to be used in times of memory forensics as well as digital investigations.

Note that The framework is one that tends to inspects and take out the memory artifacts that pertains to 32-bit and 64-bit systems. The framework has aided for all kinds of Linux, Windows, and others.

Hence, Based on the question, the Recommendation of a framework that will enable the analyst to install a kernel driver is said to be Volatility.

Learn more about Volatility from

brainly.com/question/27993482

#SPJ1

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2 years ago

(iii) ............ characters can be stored in memo field. (a) 50 (b) 64000 (c) 255 (d) 200

Svetlanka [38]

Answer:

(b) 64000

Explanation:

Assuming that the "Memo" being mentioned is a Microsoft Access memo field, it can hold up to 64,000 characters, even in the more recent version of the application where the "Memo" is now know as the "Long Text" field.

According to microsoft.com, "In earlier versions of Access, we used the Memo data type to store large amounts of text... the Long Text field works the same as the Memo field of old... [it] can only display the first 64,000 characters."

Please put "Brainliest" on my answer if it helped you out the most!

(Further Reading) If you're still confused, I suggest you search up the following:

- Microsoft Access Long Text character limit

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2 years ago

Write a definition in your own words for Raster Graphic. Do not copy and paste please.

Vlada [557]

Answer:

Raster Graphic is a bitmap. They are basically a grid of small pixels that make an image.

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3 years ago