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3 years ago

10

What is the equation of the line with the same slope as the equation x-4y=3 and the y-intercept(0,-8)?

1 answer:

kogti [31]3 years ago

6 0

Answer:

Answer:y = 1/4x -8Step-by-step explanation:First find the slope of the linex-4y =3Subtract x from each sidex-4y -x = -x+3-4y = -x+3Divide each side by -4-4y/-4 = -x/-4 +3/-4y = 1/4 x -3/4This is in the form y= mx+b where the slope is m and the y intercept is bThe slope is 1/4We want the same slopey = 1/4x +bwe know the y intercept is -8y = 1/4x -8.

Step-by-step explanation:

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Y=x+ - 4x3<br> Find the two stationary points<br> on the graph of y=x4 - 4x3

mafiozo [28]

Answer: $(0,0), (3,-27)$

Step-by-step explanation:

Given

Curve is $y=x^4-4x^3$

The stationary point on a differentiable function is the points where the differentiation of the function is zero i.e. slope is zero at that point.

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Equate it to zero

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Therefore, the stationary points are $(0,0), (3,-27)$

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3 years ago

Read 2 more answers

For questions 9 and 11, solve for the remaining angles.

maw [93]

Answer:

‹A = 141°

‹B = 28°

‹C = 11°

*These angles are rounded to the nearest whole*

Step-by-step explanation:

Because you are only given sides you can find an individual angle measures with the inverse law of cosines.

Remember the side opposite of the angle corresponds to that angle.

a² = b² + c² - 2bc cos(A) →

A = cos⁻¹ (a² - b² - c² / -2bc)

b² = a² + c² - 2ac cos(B) →

B = cos⁻¹ (b² - a² - c² / -2ac)

c² = a² + b² - 2ab cos(C) →

C = cos⁻¹ (c² - a² - b² / -2ab)

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3 years ago