Answer:e
eE
Step-by-step explanation:
Answer:
Yes, it always represent 40% of that number.
Step-by-step explanation:
Answer:
![\int_{-\infty}^{-1} x^{-\frac{8}{3}} dx = -\frac{3}{5} [-1 - \infty]](https://tex.z-dn.net/?f=%5Cint_%7B-%5Cinfty%7D%5E%7B-1%7D%20x%5E%7B-%5Cfrac%7B8%7D%7B3%7D%7D%20dx%20%3D%20-%5Cfrac%7B3%7D%7B5%7D%20%5B-1%20-%20%5Cinfty%5D%20)
So then we see that the integral not converges since the limit 
is not defined on this case.
So then this integral diverges.
Step-by-step explanation:
For this case we need to solve the following integral:
So lets solve the integral in order to see if diverges or converges:
And on this case we can evaluate like this:
![\int_{-\infty}^{-1} x^{-\frac{8}{3}} dx = -\frac{3}{5} [\frac{1}{(-1)^{5/3}} - \lim_{x\to -\infty} \frac{1}{x^{5/3}}]](https://tex.z-dn.net/?f=%5Cint_%7B-%5Cinfty%7D%5E%7B-1%7D%20x%5E%7B-%5Cfrac%7B8%7D%7B3%7D%7D%20dx%20%3D%20-%5Cfrac%7B3%7D%7B5%7D%20%5B%5Cfrac%7B1%7D%7B%28-1%29%5E%7B5%2F3%7D%7D%20-%20%5Clim_%7Bx%5Cto%20-%5Cinfty%7D%20%5Cfrac%7B1%7D%7Bx%5E%7B5%2F3%7D%7D%5D)
So then we see that the integral not converges since the limit is not defined on this case.
This integral diverges.
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