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jarptica [38.1K]
3 years ago
5

PLSSSSSSSSSSSSSSSSSSS HELPPPPPPPPPPPPPPPPPPP!!!!GUARaNTEE REWARDAmanda earned a score of 940 on a national achievement test that

was normally distributed. The mean test score was 850 with a standard deviation of 100. What proportion of students had a higher score than Amanda? Use your z table.
Mathematics
1 answer:
MrMuchimi3 years ago
8 0
To solve this question, you¨ll need to use a table of the standardized Normal distribution, or you could use a graphing calculator. The answer will be the cumulative property which will be a number with decimals. However, this represents the students who had a lower score then her, You´ll need to subtract this from 1 in order to get the opposite number, which will be the kids who scored higher. Be sure to multiply the result by 100 to get a percentage. Your answer should be 0.806 hope this helped!

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A teacher wants to see if a new unit on fractions is helping students learn. She has five randomly selected students take a pre-
mylen [45]

Answer:

Find the difference between the two scores for a number of sample distributions. Make a plot of the differences and check for outliers.

Step-by-step explanation:

Checking for Normality means basically checking if one's data distribution approximates a normal distribution.

A normal distribution is represented by a bell-shaped curve, peaking around the mean, indicating that all of the data spreads out from the mean.

Th original aim of the teacher is to check the effects of the particular added unit on the performance of students in the subject.

The teacher goes about this by testing the students before and after learning the unit.

The best way to compare of course, is to take a difference of the test scores for different samples. This first gives the idea of whether the newly introduced unit affects performance.

This set of differences is then checked for normality.

So, the best manner to make a plot of these differences. Like we mentioned earlier, a normal distribution is bell shaped. So, the plot of these differences would be a bell shaped curve if the distribution was normal and we wouldn't get a bell shaped curve if the distribution wasn't normal.

Checking for outliers help to eliminate part of data that can totally scatter the regular behaviour of the data distribution.

So, the best way for the teacher to check for normality is to find the difference between the two scores for a number of sample distributions. Make a plot of the differences and check for outliers.

Hope this Helps!!!

5 0
3 years ago
The ratio of the number of Mays necklaces to the number of Helen's necklace is 25:9. May has 100 necklaces. How many necklaces d
likoan [24]

Answer:

36

Step-by-step explanation:

25:9

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9*4 = 36

6 0
3 years ago
7/7q+21= x /5q^2-45 then x=?​
anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

3 0
3 years ago
Mrs. Ibarra wants to create a right triangle for a geometry test. She plans to use 15, 36, and 41 as side lengths.
barxatty [35]

Answer: A, C, D and E

Step-by-step explanation:

6 0
3 years ago
Using an ordered alphabet of 26 letters, how many ways are there to choose a set of six letters such that no two letters in the
mestny [16]
To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this - 
\binom {21} {6}= \frac{21*20*19*18*17*16}{6*5*4*3*2*1} =21*19*17*8=54264
Thus, the answer is that there are \boxed{54264} ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year! <em>2018</em>
5 0
3 years ago
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