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Advocard [28]
3 years ago
9

The power 3 Superscript negative 3 equals StartFraction 1 Over 27 EndFraction . Which expression is equivalent to 3 Superscript

negative 3?
StartFraction 1 Over 3 squared EndFraction
StartFraction 1 Over 3 cubed EndFraction
StartFraction 1 Over 9 cubed EndFraction
StartFraction 1 Over 3 Superscript 9 EndFraction
Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Answer:

B.  \frac{1}{3^3}

Step-by-step explanation:

We have been given an expression 3^{-3}=\frac{1}{27}. We are asked to find an equivalent expression to 3^{-3}.

We will use exponent properties to solve our given problem.

We will use exponent property a^{-b}=\frac{1}{a^b}  to rewrite our given expression.

Upon comparing our expression with exponent property, we can see that a=3 and -b=-3.

3^{-3}=\frac{1}{3^3}

Therefore, expression \frac{1}{3^3} in equivalent to  3^{-3} and option B is the correct choice.

SpyIntel [72]3 years ago
4 0

Answer:

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.   23

Step-by-step explanation:

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Answer:

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-1 < x < 4 = { 0, 1 , 2, 3 }

<em>x </em><em>is </em><em>an </em><em>integer </em><em>then the value of x </em><em>is </em>

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<em>=</em><em> </em><em>odd </em><em>integer </em><em>=</em><em> </em><em>{</em><em> </em><em>1</em><em>,</em><em>3</em><em> </em><em>}</em><em> </em>

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