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Naddik [55]
2 years ago
10

erics cell phone service costs $40.00 a month for unlimited calls. he also pays $0.02 for each text message he sends. what equat

ion represents the total cost, c, in dollars, for when eric sends t text message
Mathematics
1 answer:
KatRina [158]2 years ago
3 0

Answer:

40.021

Step-by-step explanation:

Unlimited calls = $40

Text message = $0.021

NOTE:There is a difference between the value you gave for cost of text messages in the question and the values given in the group of answers. I will use $0.021 for cost of text messages since it is common to all answer choices.

Total cost = Cost of unlimited calls + cost of text messages

C = $40 + $0.021

= $40.021

Therefore, the equation which represent the total cost in dollars for a month is 40.021

A. 40.021

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Semmy [17]

9514 1404 393

Answer:

  • 2% growth per year
  • 25,000 to start
  • 12 years
  • 31,706 currently

Step-by-step explanation:

The base of the exponent is (1 +0.02). The value 0.02 = 2% is the growth rate. It is positive, signifying a 2% rate of growth per year. (Negative values would mean decay.)

The number 25000 that multiplies the exponential term is the value of the expression when the exponent is zero. It represents the starting population.

The exponent is said to be in years, so the time is 12 years.

The current population is the value of the expression:

  25,000(1.02^12) ≈ 31,706 . . . . current population

5 0
3 years ago
An island has some portion submerged in water. Point X on the island is at negative 9 over 2 feet from the surface of the sea. P
Tamiku [17]
It means, Point X is in more depth as compared to Point Y.

Hope this helps!
8 0
3 years ago
Read 2 more answers
Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti
Arlecino [84]

Answer:

 x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10     (1)

And 2x+3y=6     (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2


8 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
(Divide the following polynomials (x5 + y5) ÷ (x + y)
stiks02 [169]

\text{Use}\ a^5+b^5=(a + b) (a^4 - a^3 b + a^2 b^2 - a b^3 + b^4).\\\\(x^5+y^5):(x+y)=\dfrac{x^5+y^5}{x+y}=\dfrac{(x+y)(x^4-x^3y+x^2y^2-xy^3+y^4)}{x+y}\\\\=\boxed{x^4-x^3y+x^2y^2-xy^3+y^4}

7 0
3 years ago
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