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ASHA 777 [7]
3 years ago
8

Solve the problems.

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

????

Step-by-step explanation:

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The perimeter of a parallelogram is 56 meters the width of the parallelogram is 8 meters less than its length find the length of
Dimas [21]

Answer:

length = 18 mt

Width = 10 mt

Step-by-step explanation:

Let the length of the field be x

width of the field be y

Hence

P=2(x+y)

P=56 (given)

56=2(x+y)

Dividing both sides by 2 we get

x+y=28   ---(A)

Also given that width of the parallelogram is 8 meters less than its length

Hence

y=x-8

or x-y=8   ---(B)

Adding A and B

2x=36

x=18

y=x-8

y=18-8=10

Hence length = 18 mt

Width = 10 mt

8 0
3 years ago
What is the value of f(−3)?
Daniel [21]
Is that the whole question ?
7 0
3 years ago
Can someone help me with number 3 pls
sergejj [24]

Answer:

hypothesis

Step-by-step explanation:

If <em>hypothesis</em> then <em>conclusion</em>

5 0
2 years ago
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
2 years ago
Let x and y be positive integers and x be greater than y. 11x/11y =
navik [9.2K]
\frac{11x}{11y} =\frac{x}{y}
7 0
3 years ago
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