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CaHeK987 [17]
3 years ago
11

The current in a stream moves at a speed of 4 mph. A boat travels 5 miles upstream and 13 miles downstream in a total time of 2

hours. What is the speed of the boat in still water?
Mathematics
1 answer:
Dimas [21]3 years ago
7 0
I believe it is 4.5mph because traveling upstream and the stream moves at a speed of 4mph would knock off 4 of the original number so if you add 4miles to the given 5 miles you get 9

The same is with the boat going downstream it is adding 4 miles to the original number so you subtract 13 and 4 and you get 9

If it took 2 hours to do that then you divide 9 by 2 and get 4.5
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B/c = x/b<br> solve for (x)(c)
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Answer:

Hi! The correct answer is x=b^2/c, c=b^2/x

Step-by-step explanation:

<em><u>~Solve the rational equation by combining expressions and isolating the variable c and b~  </u></em>

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Two swim clubs are having a membership sale. Aqua Plus is offering a two-year membership for $237.36. Water World is offering an
galina1969 [7]
Divide the price by the number of months to find the monthly rate.
<span>$237.36 ÷ 24 = $9.89 per month </span>
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8 0
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Read 2 more answers
Heidi solved the equation
Liono4ka [1.6K]

Answer:

Correct.

Step-by-step explanation:

3 0
2 years ago
Can someone help me with this question?
arlik [135]

Try this solution:

1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;

2. m∠B=m∠M=35° and m∠C=m∠N=95°;

3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°

answer: 50°

5 0
3 years ago
Solve 2 log3 x + log3 5 =125​
zepelin [54]

Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125​

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

3 0
2 years ago
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