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Alja [10]
3 years ago
15

How do I solve this??

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0
The bars represent absolute value, where the outcome is always positive: NEVER negative, so whatever is solved in between the bars will come out positive.

This problem is similar to factoring (e.g. 6(2x+3) = 12x+18).

-3 * 1 = -3
-3 * -2/3v = 2v

|-3 + 2v| = -9
= 3 + 2v = -9

3 - 3 + 2v = -9 - 3 (whatever you do to one side of the equation, you must do to the other)
= 2v = -12

2v/2 = -12/2
v= -6

Your final answer is v = -6
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Please help me I really need help
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Answer:

Step-by-step explanation:

(1) 2x - 6y = -12

(2) x + 2y = 14

There is a -6y and a +2y. Since they have opposite signs, I'll try to eliminate the y terms. (That's my choice. There is more than one way to solve these.)

Multiply eq. (2) by 3:

3x + 6y = 42

Then add the result to eq. (1) to eliminate the y terms:

2x - 6y = -12

3x + 6y = 42

------------------

5x   = 30,  so x = 6

Now plug the value of x into eq. (2) and solve for y:

6 + 2y = 14

2y = 8

y = 4

Why did I use eq. (2) to solve for y? Because it's less work. I could have used eq. (1) instead:

2(6) - 6y = -12

12 - 6y = -12

-6y = -24

y = 4

More than one way to solve.

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3 years ago
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Mashutka [201]
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