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dmitriy555 [2]
3 years ago
15

Solve please ...... thx

Mathematics
2 answers:
kati45 [8]3 years ago
3 0
The answer   to   the   questions   is   2.359
Nesterboy [21]3 years ago
3 0
2.359!!!!!!!!!!!!!!!!!!
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Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
mixas84 [53]

Answer:

Step-by-step explanation:

m∠1=m∠3

m∠2=m∠4

3*(m∠1+m∠3)=m∠2+m∠4

3*(m∠1+m∠1)=m∠2+m∠2

3×2 m∠1=2 m∠2

m∠2=3 m∠1

now m∠1+m∠2=180°

m∠1+3 m ∠1=180

4 m∠1=180

m∠1=180/4=45°

m∠3=45°

m∠2=180-m∠1=180-45=135°

m∠4=135°

5 0
3 years ago
Help me with this please ASAP
just olya [345]

Answer:

7) 13 in. Because the hypotenuse is the longest length than opposite and adjacent.

8) 12 in. Because it has 90° angle.

9) 12 in

10) 5 in

6 0
3 years ago
Lisa wants to frame her little brothers drawing as a gift to her mother.the rectangle drawing is 43.5 centimeters by 934 millime
konstantin123 [22]

Answer:

Lisa will need 273.8\ cm of wood framing

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

P=2(b+h)

In this problem we have

b=43.5\ cm

h=934\ mm

convert to cm

Remember that  1\ cm=10\ mm

h=934\ mm=934/10=93.4\ cm

substitute the values and solve the perimeter

P=2(43.5+93.4)=273.8\ cm

7 0
3 years ago
If there are 205 students in the school, which is the best estimate of the number of students that are in the 5th grade?
Mila [183]

Answer:

34 people

Step-by-step explanation:

8 0
3 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
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