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3 years ago

The second and third terms of a G.P is 6 times the fourth term. Find the possible values of the common ratio.

Mathematics

1 answer:

egoroff_w [7]3 years ago

7 0

Answer:

-1/3 or 1/2.

Step-by-step explanation:

Second term = ar, the third = ar^2 and the fourth = ar^3.

So we have the equation:

ar + ar^2 = 6ar^3

r + r^2 = 6r^3

6r^3 - r^2 - r = 0

r(6r^2 - r - 1) = 0

(3r + 1 )(2r -1) = 0

r = -1/3, 1/2.

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3 years ago

A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen

serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

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$P=\frac{8}{580}*\frac{7}{579}= 0.000167$

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f) The probability that all three are defective is given by:

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3 years ago

The second and third terms of a G.P is 6 times the fourth term. Find the possible values of the common ratio. ​

The second and third terms of a G.P is 6 times the fourth term. Find the possible values of the common ratio.