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Aloiza [94]
3 years ago
12

Let me help you out have some points and wash your hands

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

Thank you have fun in quarantine

I am Lyosha [343]3 years ago
6 0
Tysm!! Hope your quarantine is going well
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When servicing a heating boiler and radiators, a plumber knows that the time
Elena L [17]
£110 as 45mins times 4 radiators divided by 60 mins =3 hours

3 hours + 1 hour = 4 hours
4 hours times £20= £80
£80+£30=£110
3 0
3 years ago
Select the correct answer.
Umnica [9.8K]
I believe this would be a contingent discount. Contingent discounts are granted to a buyer when they satisfy certain requirements. In this case, the requirement is to have a minimum purchase of $500. Thus, that would make it a contingent discount.
The other's are incorrect.
A membership discount requires you to have a membership. 
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A bulk purchase discount is a financial incentive for regular shoppers or businesses that buy things in bulk.
8 0
3 years ago
Read 2 more answers
the floor of a shed has an area of 96 square feet. the floor is in the shape of a rectangle whose length is 4 feet less than twi
Paul [167]
Alright in this one, you are going to need to factor. 
The width is x
The length is 2x-4
To find the area of a rectangle is L*W
so (2x-4)(x) when distributed is 2x^2 -4x

Then put that in the equation and you have:
2x^2 -4x = 96
2x^2 -4x -96 = 0  

2x^2+12x-16x-96=0
3x(x+4)-4(x+4)=0
(3x-4)=0
(x+4)=0
x=-4
<u>x=3/4</u>
Since length isn't negative
we will use <u>3/4 as x.
</u>
Width= 0.75 ft
Length= 1.5

3 0
3 years ago
Week 6<br> Please answer with clear instructions so that i can apply this to other questions
Crazy boy [7]

Answer:

4

Step-by-step explanation:

Gradient is the same as slope to get your answer follow this formula y2 - y1 divided x2 -x1 in this problem it will look like this

4 - (-4) /1  - (-1) =

8 / 2 =

= 4

I hope this helps!!

3 0
3 years ago
Simplify the expression. tan(sin^−1 x)
Blizzard [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2799412

_______________


Let  \mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}

(that is the range of the inverse sine function).


So,

\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}


Square both sides:

\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}


Since \mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},} then \mathsf{cos\,\theta} is positive. So take the positive square root and you get

\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}


Then,

\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}


I hope this helps. =)


Tags:  <em>inverse trigonometric function sin tan arcsin trigonometry</em>

3 0
3 years ago
Read 2 more answers
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