All categories

3 years ago

Let me help you out have some points and wash your hands

Mathematics

2 answers:

worty [1.4K]3 years ago

7 0

Answer:

Thank you have fun in quarantine

I am Lyosha [343]3 years ago

6 0

Tysm!! Hope your quarantine is going well

You might be interested in

The value of y varies directly with x. When y=3,x=15 what is the value of y when y=10

Yuki888 [10]

If you mean the x, it would be 50

8 0

3 years ago

Serena estimates that she can paint 60 square feet of wall space every half-hour. Write an equation for the relationship with ti

Katarina [22]

Answer:

So, the relationship with i hours as the indecent variables would be

Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

Step-by-step explanation:

Since we have given that

Area that she can paint = 60 square feet

Time taken = half hour = 30 minutes = 0.5 hours

Using "Unitary method, we get that

In 0.5 hours, she can paint = 60 square feet

In 1 hour, she can paint =

In i hours, she can paint =

Let the total area she can paint be 'y'.

So, the relationship with i hours as the indecent variables would be

Now, Can Serena paint 400 square feet of wall space i. 3.5 hours

We put y = 400 and i = 3.5 hours to check whether it is equal or not.

Hence, Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

6 0

3 years ago

Read 2 more answers

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

Simplify the expression: sqrt(-25) / (5-2i) + (1-3i)

Tanzania [10]

61 would be the most simplified without expressions

5 0

3 years ago

What is the center of the circle (x + 2)2 + (y - 5)2 = 2.25?

avanturin [10]

This equation of the circle is in a center-radius form which is more generally written as,
(x - h)² + (y - k)² = r²
From the equation, the center of the circle is (h,k) and r is the radius. From the given equation above, the center of the circle is (-2,5).

3 0

3 years ago