Answer:
Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)
answer:
2y(x³+4x-2x²-8)
Part B: Factor the entire expression completely. Show the steps of your work. (6 points)
answer:
2y(x³+4x-2x²-8)
2y(x³-2x²+4x-8)
2y(x²(x-2)+4(x-2))
2y(x²+4)(x-2)
Answer:
6x - 5y = -5
Step-by-step explanation:
Your FIRST goal is to fill out y = mx + b with the values of m (your slope) and b (your y-intercept). First, find m by dividing the change in y in the two points given by their change in x. (43 - 31)/(35-25) = 12/10 = 6/5. Plug this in immediately for a "placeholder equation" of y = 6/5x + b, which you can plug either of your points into and solve for b.
43 = 6/5(35) + b
43 = 42 + b
1 = b
Your SLOPE-INTERCEPT equation is y = 6/5x + 1. However, you were asked for standard form. This means you must convert into ax + by = c, where a b and c are all whole numbers, and a is positive.
y = 6/5x + 1
-6/5x + y = 1
6/5x - y = -1
6x - 5y = -5, and this is your final answer.
Let me know if you need a more in-depth explanation on any part of this!
Answer:
y/x = 2.5
Step-by-step explanation:
y ∝ x
change ∝ to = by adding constant k or c
y = kx
Divide both sides by x
y/x = k, also k = y/x
Input the values
k = (7 1/2)/3. Change 7 1/2 to improper fraction to give 15/2
k = (15/2)/3
k = 
÷ 3
Change the division sign to multiplication which will change 3 to its inverse(1/3)
k = × 
k = 
Divide the numerator and denominator by 3 to get 5/2
k = 5/2
From y/x = k,input k into the eqn
y/x = 5/2
y/x = 2.5
Answer: 8 minimum work stations is what would be needed.
Step-by-step explanation:
The cycle time is computed as the operating time daily divided by the scheduled output.
It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.
Therefore,
If you need to produce 30units/hour.
The average cycle time is as follow:
The average cycle time is the average time between the completions of units.
60/30= 2 average cycle time
=16/2
=8
8 work stations is the minimum number that would be needed.
It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.
Answer:
4
Step-by-step explanation:
