Is there any way you can take a picture of the problem? I cannot interpret the way you asked your problem.
Answer:
The answer is the option C
Step-by-step explanation:
we know that
An isosceles triangle has two equal sides and two equal angles
The two equal angles are called the base angles, and the third angle is called the vertex angle
In this problem we have the isosceles triangle TIC
∠I=
-----> vertex angle
∠T=∠C -----> base angles
Remember that the sum of the internal angles of a triangle is equal to 
so
∠I+∠T+∠C=
∠I+2∠T=
Substitute
+2∠T=
Solve for angle T
2∠T=
∠T=
∠T=
Gotta move that b to the side ya dig
Eight and two hundred sixty one thousandths
Hello,
We know that all the angles shown add up to 360 (think of a circle).
We also know that the angle of (6x-1)° is congruent to the angle opposite of it. (the "top left" angle) = 6x - 1°
We also know that the angle of (7x-1)° is congruent to the angle opposite of it.
(the "bottom left" angle) = 7x -1°
Knowing the sum of all angles as well as the angle measures in terms of x, we can add all the angle measures and equal it to 360.
So, we get (7x - 1) + (7x - 1) + (6x - 1) + (6x - 1) = 360
Simplify and we get:
26x - 4 = 360
Add 4 to both sides to get 26x = 364
Divide by 26 on both sides to get 14.
x = 14
Hope this helps!
